Introduction:
We need to calculate the resistances necessary to get a gain of -10 and what the current coming out of the op amp would be if Vs were 1V:
Experiment:
We then build the circuit setting the Vs to 0.25 and vary it while recording the voltages across the input and output resistors. A voltage divider was used to get Vs .
The circuit was then built with a 1K Ohm load according to the following schematic:
\Data:
Inverting Op-Amp
Vin
Desire
|
V_IN
Actual
|
V_Out
Measured
|
V_Rf
Measured
|
I_op
Calculated
|
0.25
|
0.26
|
-2.59
|
2.58
|
0.026
|
0.5
|
0.52
|
-5.18
|
5.18
|
0.052
|
1
|
1.01
|
-10.11
|
9.94
|
0.101
|
For V_IN = 1V
Measured I_cc = 0.867 mA
Calculated P_cc = 12*0.867 mP = 10.404 mP
Measured I_ee = -0.979 mA
Calculated P_cc = 12*0.867 mP = 10.404 mP
Measured I_ee = -0.979 mA
Calculated P_ee = 12*0.979 mP = 11.748 mP
I_cc + I_ee = 0.112 mA
The percent error is 12% therefore, it is consistent with KCL.
I_cc + I_ee = 0.112 mA
The percent error is 12% therefore, it is consistent with KCL.
Circuit with 1k Ohms load
Vin
Desire
|
V_Out
Measured
|
V_Rf
Measured
|
I_op
Calculated
|
I_cc
Measured
|
I_ee
Measured
|
1
|
-10.02
|
9.77
|
0.1
|
0.877
|
-0.984
|
Measured I_cc = 0.877 mA
Calculated P_cc = 12*0.877 mP = 10.524 mP
Measured I_ee = -0.984 mA
Calculated P_ee = 12*0.984 mP = 11.808 mP
I_cc + I_ee = 0.107 mA
The percent error is 07% therefore, it is consistent with KCL.
Calculated P_cc = 12*0.877 mP = 10.524 mP
Measured I_ee = -0.984 mA
Calculated P_ee = 12*0.984 mP = 11.808 mP
I_cc + I_ee = 0.107 mA
The percent error is 07% therefore, it is consistent with KCL.
Conclusion:
With percent errors of 12% and 7% this experiment is considered a success and obeys Kirchhoff's Current Law. We saw that the gain depends directly on Rf/Ri.
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